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4u complex numbers (1 Viewer)

jnney

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Express -root3-i in modulus–argument form.

I got 2cis30 - the angle by doing the tan inverse of 1/root3.

Answer says 2cis(-5pi/6)


it's wrong to say 2cis30 isn't it, because the coordinate is in the 3rd quadrant?

can i say 2cis270 instead?
 
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by convention the simplest form of the argument is expressed between -pi and pi
 

Hermes1

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Express -root3-i in modulus–argument form.

I got 2cis30 - the angle by doing the tan inverse of 1/root3.

Answer says 2cis(-5pi/6)


it's wrong to say 2cis30 isn't it, because the coordinate is in the 3rd quadrant?

can i say 2cis270 instead?
theres something called the principle argument which means you angle has to be between 0 and 180, if its not you go the other way round.
-root 3-i is in the 3rd quadrant, so thats why its 7pi/6 which by principal argument regulations has to be written as -5pi/6

gud to see someone getting ahead and starting 4 unit early.
 

jnney

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theres something called the principle argument which means you angle has to be between 0 and 180, if its not you go the other way round.
-root 3-i is in the 3rd quadrant, so thats why its 7pi/6 which by principal argument regulations has to be written as -5pi/6

gud to see someone getting ahead and starting 4 unit early.
OH THAT'S RIGHT. Forgot about that for a second.


Also, for 'show that (-root3-i)^6 is a real number,

i've replaced the inside brackets with 2cis5pi/6. I dont know what to do next.
 

jnney

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what happened to the denominator 6?
 

Hermes1

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what happened to the denominator 6?
its a formula with cis that when you put it to the power of something the power gets multiplied into the argument.



do u have terry lee 4u? if not get it, he covers everything like this in good detail
 
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jnney

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Yes I have it, I'll look at it right now.

Thanks guys!
 

jnney

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Both? :D I just started 4u today so exciting LOL
 

Alkanes

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Haha nice. Yea i started it too but not this far yet. :p
 

Alkanes

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This one but just the basics like multiplying/adding i
 

Alkanes

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Lol i don't have the textbook atm. Only 4u book i have is cambridge.
 

khfreakau

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what happened to the denominator 6?
It's called De Moivre's theorem - as arj1 explained, you can simply multiply the power into the angle. However, that's not to say that you can't still expand out (cisx)^n normally by making it cosx + isinx and binomially expanding, which will come in handy in later questions :)
 

Shadowdude

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It's called De Moivre's theorem - as arj1 explained, you can simply multiply the power into the angle. However, that's not to say that you can't still expand out (cisx)^n normally by making it cosx + isinx and binomially expanding, which will come in handy in later questions :)
Ah, I got screamed at - kinda - by my Algebra lecturer for using 'cis'. Never used it again afterwards =P
 

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