General Thoughts: Mathematics (5 Viewers)

[jordiviv]

Does anybody know of any solutions posted online as of yet?
...or when some might be released?

 

[kliro_10]

nahh you had to start off saying that 0<Q<2pi and then sub in the value for Q that you found in part (i) and rearrange by splitting up the inequality and solving, then bringing it back together

 

[MadGold777]

Anyone know what band 84/120 would be?
Reps!

 

[someth1ng]

Anyone know what band 84/120 would be?
Reps!

Band 5 - should be roughly a mid-high Band 5. If you got a mark like that - expect something like 86-88.

 

[forkandspoon]

Does anyone know the ratio of the volume of the cylinder to the volume to the paraboloid?

 

[umz93]

What do you think the cut-off will be?

 

[mitchh81]

not sure but did everyone get units
for the volume for 8bi

 

[Galladrim]

Pretty happy, went better than I thought I would. Thankfully its all over. Never have to do Mathematics again!!!!!

 

[forkandspoon]

not sure but did everyone get units
for the volume for 8bi

i dunno. i got (pi)(h^2)/2...

 

[jgalpin]

no, it increased by 6.3%

 

[jgalpin]

i got pi h^3 / 3 coz u had to intergrate c^2

 

[jgalpin]

+1

 

[jgalpin]

No it wasn't....... it was a geometric series not limiting sum, answer came out to be around 23.98

 

[gunat61]

what raw mark do you reckon you would need for 85?

 

[Kimbles2011]

I just want a band 6 - what do you think will be the raw score for 90%?

 

[forkandspoon]

i got pi h^3 / 3 coz u had to intergrate c^2

Huh? why? What do you think i did wrong? i found the volume about the y axis. so V= (pi) integral of (x^2) dy. But y=x^2 sooo...
Therefore, integral of (y)dy from 0 to h. Therefore, = (pi)(Y^2)/2.. now i subbed in limits: (pi)(h^2)/2.. where did the 'c' come from?

 

[forkandspoon]

I just want a band 6 - what do you think will be the raw score for 90%?

94/120 or 95/120. so around 79%

 

[Kimbles2011]

94/120 or 95/120. so around 79%

Thanks for replying I think that's quite achievable

 

[umz93]

Thats what I thought, because it was a definite integral!

 

[forkandspoon]

So is it (pi)(h^2)/2........or.......(pi)(h^3)/3