series question. (1 Viewer)

[Mdzabakly]

find the values of all pronumerals if these series are geometric
d) 1/4,t,1/9
e)y,2,6

 

[Menomaths]

find the values of all pronumerals if these series are geometric
d) 1/4,t,1/9
e)y,2,6

Since they are geometric, (1/9)/t = t/(1/4)
Cross multiply you get t^2 = 1/36
Square root both sides you get 1/6
therefore t = 1/6

Since they are geometric, 6/2 =2/y
Cross multiply you get 6y = 4
Divide both sides by 6 you get y =4/6 =2/3

 

[ocatal]

d) t / (1/4) = (1/9) / t
Then cross multiply to get:
t^2 = 1 / 36
And solve for t:
t = 1 / 6

e) 2 / y = 6 / 2
2 / y = 3
And solve for y:
y = 2 / 3

 

[ocatal]

Since they are geometric, (1/9)/t = t/(1/4)
Cross multiply you get t^2 = 1/36
Square root both sides you get 1/6
therefore t = 1/6

Since they are geometric, 6/2 =2/y
Cross multiply you get 6y = 4
Divide both sides by 6 you get y =4/6 =2/3

Beat me to it haha..

 

[Menomaths]

Beat me to it haha..

 

[Menomaths]

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