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HSC 2013 Maths Marathon (archive) (2 Viewers)

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Sy123

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Re: HSC 2013 2U Marathon

My bad, 0.75n?
If n = say 10, then your probability becomes greater than 1 :p
Just imagine n to be any other regular number, do it for 5 numbers first, then try to do it for any number n
 

Menomaths

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Re: HSC 2013 2U Marathon

If n = say 10, then your probability becomes greater than 1 :p
Just imagine n to be any other regular number, do it for 5 numbers first, then try to do it for any number n
Oh my god....0.75n?
 

Menomaths

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Re: HSC 2013 2U Marathon



I'll leave it to you to explain why it is. i.e. I've turned the question into a 'Show that'
Shit, I'll think about it this time...My name holds true so far :(
 

integral95

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Re: HSC 2013 2U Marathon

[/QUOTE

1. Change cotx into cosx/sinx
2. multiply top and bottom of the fraction by sinx
3. Now you should realise that the differentiation of the bottom equals to top.

Hence the answer is ln(sinx - cosx)
 

Sy123

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Re: HSC 2013 2U Marathon

I don't think 2 unit learn angle sums...
don't be fooled, you will not need to use any 3U knowledge here :p

You don't need to actually differentiate sin(x) using first principles, I am asking that using the differentiation from first principle, i.e.:

Using the fact that:



Prove the limit above.
 
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Sy123

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Re: HSC 2013 2U Marathon

This proof would probably be accepted at 2U level, same concept is used in loan repayments/annuities etc
However above that I don't think it would be accepted at 3U and above

Better proof:

 
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omgiloverice

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Re: HSC 2013 2U Marathon

Ahh... that makes alot more sense, I was wondering how to show the solution in an more formal sense.

don't be fooled, you will not need to use any 3U knowledge here :p
I'm sorry Sy I will never doubt you again.
 

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Re: HSC 2013 2U Marathon

No. Sorry, that was my bad drawing! The line corresponding to the 45degree angle should be lower than the first line (I had intended to draw it like that initially, but as you can see I forgot to). The length of the ladder is given by 'L' which is the same on both lines :)
 
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