for part d i just got the tables for both equasions(y=cosh(x), y=1.007518(x^2) +1) and made the x values of both corrispond to compare the y values. you minus one form the other and find the absolute value of the result. (eg y=coshx, when x=2.7, y=7.47347 and y=1.007518(x^2)+1 when x=2.7...