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And that scholarship offer pretty much covers the cost of any course (the amount is above any HECS band, and 99.95 gets you into any course) So, essentially it is true.

1/3 =/= 3.333333, nor does it equal 0.333333. 0.33333 is merely a rounded representation of the rational number 1/3. Yes, if you multiply that rounded figure by 2, you obtain 2/3 = 0.66666. However, as you probably know, 0.666...6667 is a better approximation for 2/3. It is for this same...

When did the interview offers come out for Sydney?

Answer is 45ms^-1 to the right. Probably half for omitting the direction. If you assume 'land' to mean the instant it first touches the ground, it would still technically have this component of its velocity. It isnt until the ground exerts a force on the ball that the motion is retarded, and...

From last year, 96.15 would have got a bonded place. For a full CSP, the cut-off was still 99.10 for the UMAT stream (99.75 for UMAT/ENTER stream and 99.90 for ENTER stream)

Here some advice that might help with the 35% in maths - use decimal places in your numbers. '98' and '9.8' do NOT mean the same thing. And if you work hard, you might just achieve that UAI of 9.8+

Basically your just saying that you get a shitload of money for getting decent scores arent you? A car (10k) and up to 15k for basically doing nothing.

Aim for 100 - and if you fall a few points short, who cares? Better than aiming low and not having any chance of achieving a high score.

How much is the cut-off lowered for getting 99.xx?

Its a myth that ranks are most important. The moderation procedure isnt as simple as allocating the best internal mark to the first internal, the second to the second, and so on. The differences in marks are considered. The only thing that ranking dictates is the final order of the internal...

Are you just talking about sign diagrams? This new 'advanced' method is basically just common sense. If you hvae all the real zeroes of the derivative and know whether they are single or repeated (either odd or even), then constructing the diagram is basically logic. If the derivative = 0, there...

That one is possible though: S(xe^(x^2)dx =(1/2)S(2xe^(x^2)dx =(1/2)(e^(x^2)) +C Whereas the one posted first is the one posted first appears to have calculated the derivative instead of integral.

The most obvious thing to consider is that infinite is not finite. it is not a number, it has no value; rather, it is a concept. Therefore,