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Was the answer they got $270? Because it looks like they have subtly worded the question differently to what is normally asked. They didn't technically ask for the financial expectation of the game, rather they asked for the expected returns if you pay $300 (i.e. 10 games). I have never...

The difference between a straight compound interest question and an annuity (future value) can be very subtle if they don't specify. Compound Interest Wording: Bob invests $1000 for 10 years at 5% p.a. compounding annually. How much does he have at the end of the investment? Future Value...

I am not sure exactly what the smart start quiz is, but looking at the website it seems similar to the ILIP quiz of old. The repercussions of not completing the quiz is that the library will withhold your final marks (same thing they will do to you if you fail to pay fines by the due date)...

To put spaces in between words in <a href="http://www.codecogs.com/eqnedit.php?latex=\LaTeX" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\LaTeX" title="\LaTeX" /></a>, you can use the command \text{Type in your text here}

To begin, I haven't had time to read in detail what everybody has written yet so I apologise if what I say has been said before. Firstly, I know this won't change your overall argument, but from what I can tell of you Scorch, you seem to be the kind of person who likes to corrected when...

Who says 1 = -1 is false, afterall: <img src="http://www.codecogs.com/eq.latex?\begin{align*}i&=i\\\sqrt{-1}&=\sqrt{-1}\\\sqrt{\frac{-1}{1}}&=\sqrt{\frac{1}{-1}}\\\frac{\sqrt{-1}}{\sqrt{1}}&=\frac{\sqrt{1}}{\sqrt{-1}}\\\sqrt{-1}&=\frac{1}{\sqrt{-1}}\\(\sqrt{-1})^{2}&=1\\\therefore...

That's right: <img src="http://www.codecogs.com/eq.latex?\begin{align*}y&=\frac{u}{v}\\y'&= \frac{u'v-v'u}{v^2}\end{align}">

Not for the product rule as it is adding and multiplying everything so it will not matter the order that you do things in. But just remember it does matter for the quotient rule because you have to subtract and divide your u's and v's, so if you mix them up you will get a completely different...

You haven't done anything wrong, that is the correct answer and method. And yes, e^x = 0 has no solutions.

This looks very much like a question about the orbital period of a planet (all your variables and the answer are correct for the planet Mars). Which means your equation is slightly incorrect. Kepler's law of periods is: <img src="http://www.codecogs.com/eq.latex?T^{2} =...

I don't know if it is official or if it is just good manners, but most often classes start at 25 mins too the hour (if not later) and finish 25 mins past the hour (if not early). So you should have about 10 mins between classes. Of course there are always those lecturers and tutors that have...

One place that I can recall it mentioned is in one of Paul's letters to the the Corinthian Church:

I had a sinking feeling that I misunderstood as soon as i pressed post but I did not have time to edit. Oh well, taking what I said from the specific to the general. My experiences of lecturers outside the physics department is that they are actually quite reasonable and if you haven't got...

I don't think it will be a big deal if you can't get to the phys tuts. They are only running two of them in the session(or so the timetable says) and most, if not all, of the physics lecturers have an open door policy so if you are struggling with the Mastering Physics questions or the...

Good point, well made. Clearly, differentiating my answers showed that only the +ve solution holds true (also looking over it again, I realise I dropped my + C). But I can not see any reason why if u^2 = x + 2, then u only equals +sqrt(x+2) After all, if you were to graph u^2 = x + 2...

I am going to go against popular opinion and say that it is not entirely correct. Firstly the mistake, if u^2 = x + 2 then u = sqrt(x + 2) AND u = -sqrt(x + 2) e.g. if x = 7, then u^2 = 9 but then u could be either +3 or -3. So unless you are going to take both cases and do the...

13 b) A = 500 - 10x - 4000 / x = 500 - 10x - 4000x^-1 A' = -10 + 4000x^-2 Set A' = 0 for turning points 0 = -10 + 4000x^-2 1 / 400 = x^-2 x^2 = 400 Therefore, x = 20 and x = -20 (but we can ignore the -ve answer as that is not a physically possible result in this case). To show x...

I think I have an answer for i) (but there may be a simpler method) To begin with, you need to find a relationship to explain how the radius of the cylinder affects the height of the cylinder. Because we know the cylinder has to be contained by a cone, then we can say that there is a linear...

There is no physical reason why gravitational potential energy is negative. The key of potential energy (any potential energy, not just gravitational) is where you define it to be equal to 0 and you are allowed to define this point to be anywhere. However once that point is defined, then...

I think the book might be wrong. When I worked it out, I got the same answer and when I plugged the question into wolframalpha.com, it also gave the same result. The input I used in wolframalpha was: integrate integrate exp(y/x) dy from y = 0 to y=x^3 dx from x = 0 to x = 1