Search results

first thing that comes to mind is that there is a change from theta on the LHS to theta/2 on the RHS so u could try using double angle formula. and heyyyy, tht means you can get rid of the 1's in both brackets. and then de moivre's from then on

count me in as well

A^2 x^2 =4 not Ax^2 =4

Re: HSC 2013 4U Marathon I'd assume it's meant to be 1-cos(theta)-isin(theta) for the denominator. In which case, I think using double angle formulae will work out.

Re: HSC 2013 4U Marathon haha yeah, dw its 12:30. Heads get all screwy.

Re: HSC 2013 4U Marathon Oh right, not sure if 1st line is right. But I think the question is leading on into expressing z^(2n+1) -1 in (z-z1)(z-z2)(z-z3)... form, where z1, z2, z3... are roots of z^(2n+1)=1

Re: HSC 2013 4U Marathon not quite; but i'm curious as to how you came to that

Re: HSC 2013 4U Marathon oh, factorise into a bunch of quadratic factors

Re: HSC 2013 4U Marathon aaah, I see =/

Re: HSC 2013 4U Marathon a) Find, in modulus-argument form, the roots of the equation z^(2n+1) =1. b) Hence factorise z^2n + z^(2n-1) + ... + z^2 + z +1 into quadratic factors with real coefficients. c) Deduce that 2^n * sin(pi/(2n+1)) * sin(2pi/(2n+1)) * sin(3pi/(2n+1)) ...

Re: HSC 2013 4U Marathon Expressing 957 in its prime factors: 3*11*29 Now, a^2 - b^2 = (a-b)(a+b)=957 So now, take turns making a+b and a-b, from the factors of 957. 1. let a+b=957 a-b=1 2a=958 therefore, a = 479, b=478 2. let a+b=3*11 a-b=29 2a=62 therefore, a=31, b=2 3. let...

Re: HSC 2013 4U Marathon Lol, is the answer a = 479, b=478; c=31, d=2; a=45, b = 42; c=161, d=158

if the dash is supposed to be there for the 3rd q, it's a whole different story.

http://www.boardofstudies.nsw.edu.au/archives/syllabus_hsc/economics-amendments-2011.html Main points to note: - addition of United Nations, OECD, G20 and G7/G8 in 'Trade, financial flows and foreign investment' section (p 31) TOPIC 1 - rewording of the case study requiring study of the...

For (i) Since, you know that Q is P rotated -90 clockwise, you just multiply P by cis (-pi/2)

Well, put simply, by squaring both sides, you're effectively changing the equation to whole new different equation. For example, consider the equation x=1. Now, this is the same as asking where on the Cartesian plane, does the line y=x intersect with the line y=1. Now obviously, there's only...

http://www.boardofstudies.nsw.edu.au/syllabus_hsc/pdf_doc/maths23u_syl.pdf The syllabus is split into topics. i.e. Topic 1 is Basic Arithmetic and Algebra Topic 2 is Plane Geometry ... Topic 10 is Geometrical Applications of Differentiation ... Therefore, I would think that your assessment...

Alright cool. Good luck for your future studies. =D

lol no problem. If it continues to produce an error, I can send it to your email if you want. Although, I must warn, that these solutions are really dodgy sometimes. i.e. they skip steps and usually provides unsatisfactory working out, in terms of marking criteria and also uses really dodgy methods.