Search results

5 mod 317. 317 = 5 * 63 + 2 5 = 2 * 2 + 1 2 = 1 * 2 + 0 GCD(317, 5) = 1. 1 = 5 - 2 * 2. How would you finish this via substitution? For example, 2 = 317 - 5 * 63. Correction: 1 = 5 - 2 * 2 1 = 5 * 1 + 2 * - 2 1 = 5 * 1 + (317 - 5 * 63) * - 2 1 = 5 (1 + 126) + 317 (-2) 127 = inverse.

5 mod 317. 317 = 5 * 63 + 2 5 = 2 * 2 + 1 2 = 1 * 2 + 0 GCD(317, 5) = 1. 1 = 5 - 2 * 2. How would you finish this via substitution? For example, 2 = 317 - 5 * 63. Correction: 1 = 5 - 2 * 2 1 = 5 * 1 + 2 * - 2 1 = 5 * 1 + (317 - 5 * 63) * - 2 1 = 5 (1 + 126) + 317 (-2) 127 = inverse.

Don't be too harsh, I'm not even in Year 11.

A conical fuel tank is 2.5m deep and has a top diameter of 2m. Fuel is withdrawn from the tank at a rate of 0.25 m³ /min. At what rate is the level of fuel falling at the instant when the depth of fuel is 1.5m?

A conical fuel tank is 2.5m deep and has a top diameter of 2m. Fuel is withdrawn from the tank at a rate of 0.25 m³ /min. At what rate is the level of fuel falling at the instant when the depth of fuel is 1.5m?

Again, you didn't prove anything. I hope it is not Allah that forms part of your little worldview. Truly, I hope not; because that is such a cliché. Everybody lives in delusion; that is due to the nature of everybody having a worldview. Social conditioning is the greatest proponent of religion...

No, you don't know that. One can conjecture about anything which hasn't been proven.

y = { 0 when x <= 0 { x when 0 < = x

(3, 2, 0) and is parallel to (1, 2, 3). Write the equation of L in parametric form. Please explain the steps.

Yeah, nice one.

The Q. is to sketch the region formed by this expression --> arg(z + 2 - 3i) = π / 6. Let z = x + iy...

Yeah, pi / 2. I started doubting it after doing so many of them.

If w1 = -√3 + i is a cube root of z. Find z. Is there any quick method to getting the original angle (arg(z))? I don’t understand that part, in particular.

Correct. It forms every complex no. (& thus every real no.).

... look like if k was allowed to vary over all possible complex no.s? Note, z = 3+9i. k = every possible complex no. (& obv. all the purely reals too).

Simplify (1 + i / 1 - √3i)9. Many thanks!

Nice, that is the method I used (except 3pi / 4 should be 5pi / 4).

Use De Moivre's theorem to find all z where (i) z^2 = i

Find the modulus of the following complex no. without multiplying into cartesian form: (a) 2 + 8i / 2 - 3i

Factorise (a) 3(a2 + 2b2) – (a + b)(a2 + 2b2) (b) (a + b)4 + (a - b)2(a + b)2 (c) (x + y)x2 – (x + y)y2