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  1. H

    Q16

    Re: Q16 part c Well, here's how I did it; c/ (i) x^2 + (y - c)^2 = r^2 ----(1) y= x^2 ----(2) sub (2) into (1) y + y^2 - 2cy + c^2 - r^2 = 0 y^2 + (1 - 2c)y + (c^2 - r^2) = 0 delta = 0, because it 'touches', not cuts delta = (1 -...
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