Search results

Ahh jesus i'm an idiot. I've done a thousand questions around the Y axis and I just got stumped :[ Thanks for the help

I don't understand how the boundary changes from 0-9 to 0-3. Can you explain that? I also subbed in 3 for 9 = Pi * [ 81(3) - [18(3)^3]/3 + [(3)^5]/5 - 0 ] = Pi * [ (243) - (162) + ([243]/5) - 0 ] = 407.150

The area in the first quadrant bound by y = (9 - x^2), y=0 and y=9 is rotated about the y axis. Calculate the volume of the solid generated. I keep getting: Pi * Integral between 9/0 (9-x^2)^2 = " 81 - 18x^2 + x^4 - 0 = " 81x - [18x^3]/3 + [x^5]/5 - 0 = Pi * 81(9) -...