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Correct. Which numbers should I ring to fix this?

I plan on transferring to Chiropractic. I got a uai of 83 but the cut-off is 83.45. Would there be any way of me getting directly into Chiropractic without having to do a year of Non-Award study? Cheers.

G'Day All, I need to apply for Non-Award study (late, I know) and I need these two documents: Advice of uai from uac. HSC Record of Achievement. I believe these were supposed to be mailed to me but I never recieved them. What numbers do I need to call so that I can get copies of...

Find the cost to host 200 people, which I think was $3100. Find the ticket price to break even at $3100. 3100/200 = $15.5 I think. Find the ticket price to make $1500. 1500/200 = $7.5. Add the two together, $23.

94 or 95, sweet.

I'm still not getting the difference between continous and discrete, more examples?

Lol, the first ticket drawn gets first prize. ;)

That's my major problem; I get nervous and rush through a whole page of working out only to realise I for got to divide 8.4% p.a by 12 months. :D

Or: (1/200) x 100 + (1/199) x 50 - 1/200 x 1 - 1/199

That's not financial expectation, if you said that you'd be wrong.

Basically it works like this. 68% lie within 1 standard deviation. I.e, between - 1 and 1 z-scores. 95% lie with in 2 standard deviations. I.e, between -2 and 2. 99.7% lie within 3 standard deviations. I.e, between -3 and 3. By using simple deduction yo can work it out.

Easy, tiger.

If 40 is the mean, then 50% lie below 40. 52 is one standard deviation above the mean. 34% of scores lie between 0 and 1. Therefore 50 + 34 = 84% below 52.

Normal distribution. 84%. 50% + 34%.

That last one I did was done for two prizes of $1000, didn't read the question properly. I think it's -$5.96.

What's the answer in the book?

I'll do it again. Financial expectation = (2/500) x 1000 + (1/499) x 1000 - 2 x 5 = -$3.99

Financial expectation = (2/500) x 1000 - 2 x 5 = -$6 That right?

Ok, let's say I measure something to be 250 mm, to the nearest mm. Therefore the possible error is 0.5 mm. Therefore % error = (0.5/250) x 100 = 0.2% Basically, find the error in terms of measurement (i.e, mm, or m, or whatever) and divide it by the whole measurement, and then...

Ok arc length = (theta/360) x 2 x pi x r That is the same as saying: arc length = (theta x 2 x pi r)/360 So you take the 360 to the left: (arc length x 360) = theta x 2 x pi x r Now you want to get rid of 2 x pi x r, so: (arc length x 360) / (2 x pi x r) = theta. I can't...