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What about 0 < A(-(1/3^(3/2))) - A/-(3^(1/2)) + 1 Giving A >- 3.3^(1/2) /2 and when A=0 there are on zeros as f(x) =1. Therefore one zero only when 0< absolute A <3.3^(1/2) /2. Also, shouldn't the question have said one REAL zero?- oneeye
- Post #14
- Forum: Mathematics Extension 1
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