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grrr... I knew it would turn out to be simpler than I thought. :) maybe next time I'll go back and look at the definition of a logarithm before asking stupid questions. Thanks!

Just when I thought I was getting good at integration and logarithms, I encountered this question: Find indefinite integral of 3^(2x-1) I'm sure the method wil turn out to be quite simple-- I just want to know how to get to the solution [3^(2x-1)]/2ln3. Any help would be greatly appreciated!