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2qns (1 Viewer)

Thread starter bos1234
Start date Jun 23, 2007

B

bos1234

Member

#1

Last edited: Jun 23, 2007

M

malady

New Member

#2

u=exp(x)>>du = exp(x)dx
I=Int[ 1/(u-1)-1/(u+1)]du
= 1/2[ln(u-1)-ln(u+1)] etc...

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