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arcsin(sin2) (1 Viewer)

akukei

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Extension 1 exam tomorrow!

Find the exact value of arcsin(sin2)

the answer is pi - 2 but i'm having trouble getting it...
 

vds700

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akukei said:
Extension 1 exam tomorrow!

Find the exact value of arcsin(sin2)

the answer is pi - 2 but i'm having trouble getting it...
arcsin(sinx) = x for -pi/2 < x < pi/2

an angle of 2 radians is in the 2nd quadrant, so we need to find an equivalent in the first quadrant.

using the result, sinx = sin(pi - x).

arcsin(sin2) = arcsin[sin(pi - 2)] = pi - 2
 
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