A 0.1M solution of acetic acid at 50 degrees Celsius has a pH of 2.6. What is the concentration of water in the solution at this temperature?
CH3COOH + H20 --> H30+ + CH3COO- (reversible reaction)
Ive used the pH= -log (H+) formula to find that the concentration of H3O+ to be 10^-2.6 and CH3COOH to be 0.1-10^-2.6
But how do I calculate the concentration of water? I thought the concentration of water doesn't change. The answers say its 50.6M??
CH3COOH + H20 --> H30+ + CH3COO- (reversible reaction)
Ive used the pH= -log (H+) formula to find that the concentration of H3O+ to be 10^-2.6 and CH3COOH to be 0.1-10^-2.6
But how do I calculate the concentration of water? I thought the concentration of water doesn't change. The answers say its 50.6M??