theprodigy said:
far out.. this questions got me wrappedround.. and i think its really simple too
If Z is a complex number such that Z + 1/z is real, prove that either Im(z) = 0 or |z| =1
Okay, we have Z is complex, Z + 1/z is real.
That means Im(Z + 1/z) = 0
The imaginary part of a complex number, say x, is (x-conjugate(x))/2i
For x = a + bi.
x - conjugate(x) = a + bi - (a - bi) = 2bi, and 2bi/2i = b, which is the imaginary part of x.
Apply this, by letting x = Z + 1/z
So Im(Z + 1/z) = ((Z + 1/z) - conjugate(Z + 1/z))/2i = 0. (We can ignore the denominator of 2i)
(Z + 1/z) - conjugate(Z) - conjugate(1/z) = 0
(Z - conjugate (Z)) - (1/z - conjuagte(1/z)) = 0
2i*Im(Z) - (2i*Im(z)/|z|
2)=0
This question has infinite solutions, as they are 2 variables, and only one equation restricting them. I think both the z's are the same case.
Here's a scenario which contradicts the question.
Assume Im(z) =0. Then 1/z is obviously real. But Z is complex. Hence Z+1/z cannot be real.
Assume |z|=1, 1/z = conjugate(z)/|z|2 = conjugate(z), which is complex.