frenzal_dude
UTS Student
ABCD is a parallelogram. The coordinates of A,B and C are (-1,4), (4,6) and (2,7) respectively. Find the coordinates of D.
I got D(1,3) but the answer says: D(-3,5)
Working out:
mAD = (7-6)/(2-4) = -1/2
AD: y = (-1/2)x + 7/2
mBD = (7-4)/(2+1) = 1
BD: y = x + 2
Find the intersection which is the coordinates of D:
(-1/2)x + 7/4 = x + 2
x = 1, y = 3
Please let me know if you get my answer aswell, I'm not sure if the answer given is wrong.
I got D(1,3) but the answer says: D(-3,5)
Working out:
mAD = (7-6)/(2-4) = -1/2
AD: y = (-1/2)x + 7/2
mBD = (7-4)/(2+1) = 1
BD: y = x + 2
Find the intersection which is the coordinates of D:
(-1/2)x + 7/4 = x + 2
x = 1, y = 3
Please let me know if you get my answer aswell, I'm not sure if the answer given is wrong.