D Dio-Rama Member Joined Apr 10, 2006 Messages 54 Location everywhere as everything Gender Female HSC 2006 Jun 15, 2006 #1 Find the gradient of the tangent to the curve y=tan3x at the point where x= pi/9. please help!!
Trev stix Joined Jun 28, 2004 Messages 2,035 Location Pine Palace, St. Lucia, Brisbane. Gender Male HSC 2005 Jun 15, 2006 #2 y=tan3x dy/dx=3sec<sup>2</sup>3x when x=pi/9 dy/dx=3 * 1/[cos<sup>2</sup>(3*pi/9)] = 3 * 1/[(1/2)<sup>2</sup>] = 12.
y=tan3x dy/dx=3sec<sup>2</sup>3x when x=pi/9 dy/dx=3 * 1/[cos<sup>2</sup>(3*pi/9)] = 3 * 1/[(1/2)<sup>2</sup>] = 12.
D Dio-Rama Member Joined Apr 10, 2006 Messages 54 Location everywhere as everything Gender Female HSC 2006 Jun 15, 2006 #3 thanx dude