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Differentiation question (1 Viewer)

BlueGas

BlueGas

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Okay so differentiate logtan3x, I done that and I got 3 sec^2 3x/tan3x, but the final answer says 3/sin3x . cos3x (the dot between sin3x and cos3x is a times), how do you get the final answer?
 
enigma_1

enigma_1

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3sec^2 3x/tan3x

= 3/cos^2 3x x 1/tan3x

= 3/cos^2 3x x cot3x

= 3/cos^2 3x x cos3x/sin3x

=3/sin3x . cos3x
 
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