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dry cell (1 Viewer)

zinc

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is the cathode the graphite core or the graphite, the manganese dioxide and the ammonium chloride or is the ammonium chloride the electrolyte? Very confused.
Thanks
 

SkimDawg

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anode: Zn ----> Zn(2+) +2e
cathode: NH4(+) + MnO2 + H2O + e ---> Mn(OH)3 + NH3
the carbon graphite rod is the cathode. the zinc casing is the anode. the C, MnO2 and NH4Cl im pretty sure is the electrolyte (the paste is like a mixture of the 3)
 

danz90

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SkimDawg said:
anode: Zn ----> Zn(2+) +2e
cathode: NH4(+) + MnO2 + H2O + e ---> Mn(OH)3 + NH3
the carbon graphite rod is the cathode. the zinc casing is the anode. the C, MnO2 and NH4Cl im pretty sure is the electrolyte (the paste is like a mixture of the 3)
the electrolyte past is made up of NH4Cl / ZnCl2 . MnO2 is the oxidant, and skimdawg rightly said that C(s) is the cathode.

Those equations for oxidation and reduction are also correct ;)
 

totallybord

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for the reduction half eqn, i got another eqn from another textbook
2MnO +2NH4+ + 2e ->Mn2O3 +H2O + 2NH3
?
is that still ok?
 

danz90

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totallybord said:
for the reduction half eqn, i got another eqn from another textbook
2MnO +2NH4+ + 2e ->Mn2O3 +H2O + 2NH3
?
is that still ok?
from knowledge, the oxidant is MnO2, not MnO.
So then, you use:

Oxidation: MnO2(s) + NH4+(aq) + H2O(l) + e- ---> Mn(OH)3(s) + NH3(aq)
 

totallybord

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yeah sorry its 2MnO2 and the rest of the eqn
is that wrong still ?
 

danz90

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totallybord said:
yeah sorry its 2MnO2 and the rest of the eqn
is that wrong still ?
hmm, there shouldn't be a 2 in front of all the species.
its a 1:1:1:1 stoichiometric ratio.
 

Azreil

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Maybe it was put like that to balance out the e on both sides and hence determine the final equation?
 

danz90

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Azreil said:
Maybe it was put like that to balance out the e on both sides and hence determine the final equation?
yeah, good point.
 

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