the electrolyte past is made up of NH4Cl / ZnCl2 . MnO2 is the oxidant, and skimdawg rightly said that C(s) is the cathode.SkimDawg said:anode: Zn ----> Zn(2+) +2e
cathode: NH4(+) + MnO2 + H2O + e ---> Mn(OH)3 + NH3
the carbon graphite rod is the cathode. the zinc casing is the anode. the C, MnO2 and NH4Cl im pretty sure is the electrolyte (the paste is like a mixture of the 3)
from knowledge, the oxidant is MnO2, not MnO.totallybord said:for the reduction half eqn, i got another eqn from another textbook
2MnO +2NH4+ + 2e ->Mn2O3 +H2O + 2NH3
?
is that still ok?
hmm, there shouldn't be a 2 in front of all the species.totallybord said:yeah sorry its 2MnO2 and the rest of the eqn
is that wrong still ?
yeah, good point.Azreil said:Maybe it was put like that to balance out the e on both sides and hence determine the final equation?