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Galvanic cell calc's (1 Viewer)

Mr Chi

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I forgot how to do this but i want to compare my answer.

What mass of ZnSO4 do you need to make 200ml of 1M solution?

////same with CuSO4

Also, with galvanic cells does putting more solution in a half cell effect voltage or current. What other trends are there with galvanic cells and voltage and current?
 
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anodes & cathodes and all of that business...
anode is oxidised (generally the more reactive metal)
cathode is reduced.
eg. Cu/Cu2+//Zn/Zn2+
zinc is the more reactive metal therefore it is oxidised...
ummmmm... the flow of electrons is indicated by the needle of the voltmetre....that is all i can think of for now, didnt have chem 2day. do you have a prac assessment task on setting up a galvanic cell??
 

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What mass of ZnSO4 do you need to make 200ml of 1M solution?

////same with CuSO4


Calculate the mass of 1 mole of both solutions. A 1M solution is 1 mole of solute dissolved in one litre of solvent, off the top of my head, so then you divide the mass by 5 to get 200 mL.


Also, with galvanic cells does putting more solution in a half cell effect voltage or current. What other trends are there with galvanic cells and voltage and current?

The more solution you put in, the longer the cell can supply current for. The greater the surface area of your electrodes, the more current a cell can supply. I'm not sure about this as I found this information researching my galvanic cell assignment, and they weren't in the textbook.


I_F
 

Riviet

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This how i remember it:
Oxidation occurs at the anode- AN OX
Reduction occurs at the cathode- RED CAT
This is from the Chemistry Contexts 2 textbook.
 

tennille

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Mr Chi said:
I forgot how to do this but i want to compare my answer.

What mass of ZnSO4 do you need to make 200ml of 1M solution?

////same with CuSO4
concentration = moles/volume.

Find the amount of moles of each solution by multiplying the concentration by the volume in litres. Then divide your answer by the molar mass to find the mass in grams.
 

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