Q: Which 2-digit number is equal to the sum of its first digit plus the square of its second digit?
please show how you work out, thanks.
Let x and y be integers from 0 to 9 (inclusive)
And x is the first digit and y is the second
Let z be the number we are looking for, according to your property
Now if put x in and it comes out that y is an integer, then that pair of x and y are the ones we are looking for, we will only take the + case becasue we are only looking at positive numbers here
So put in your calculator
.
.
.
The one that gives us an integer is 8.
So x=8
y=9
Therefore the number is 89
(obviously there are more elegant ways to find what numbers of 1+36x are square)