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Help please (1 Viewer)

mc1007

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Joined
Sep 8, 2009
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HSC
2011
Can someone show me how to do this please?
much appreciated!maths.jpg
 
Joined
Feb 4, 2011
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HSC
2009
= integral sin^2 (3x) sin(3x) = integral ( 1-cos^2 (3x) ) sin(3x) dx

now sub u= cos(3x) and remember to change the limits of the integral
 

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