L linxicm Premium Member Joined Feb 14, 2005 Messages 18 Gender Female HSC 2005 Sep 3, 2008 #1 Can anyone help me with this question? first derivative for : f(X)=1/(X*LnX^2) and f(x) = 98+5x/(3x^2+1) many tks!!!
Can anyone help me with this question? first derivative for : f(X)=1/(X*LnX^2) and f(x) = 98+5x/(3x^2+1) many tks!!!
L lolokay Active Member Joined Mar 21, 2008 Messages 1,015 Gender Undisclosed HSC 2009 Sep 3, 2008 #2 using quotient rule: d/dx u/v = (v.du - u.dv)/v2 ln[x2] = 2lnx d/dx 1/(2x ln[x]) = -(2ln[x] + 2)/(2x ln[x])2 = -(ln[x] + 1)/4x2lnx d/dx (98+5x)/(3x2 + 1) = ( 5(3x2 + 1) - 6x(98+5x) )/((3x2 + 1)2 = ( -15x2 - 588x + 5 )/(3x2 + 1)2 there's a derivative solver here: http://calc101.com/webMathematica/derivatives.jsp#topdoit Last edited: Sep 3, 2008
using quotient rule: d/dx u/v = (v.du - u.dv)/v2 ln[x2] = 2lnx d/dx 1/(2x ln[x]) = -(2ln[x] + 2)/(2x ln[x])2 = -(ln[x] + 1)/4x2lnx d/dx (98+5x)/(3x2 + 1) = ( 5(3x2 + 1) - 6x(98+5x) )/((3x2 + 1)2 = ( -15x2 - 588x + 5 )/(3x2 + 1)2 there's a derivative solver here: http://calc101.com/webMathematica/derivatives.jsp#topdoit
L lolokay Active Member Joined Mar 21, 2008 Messages 1,015 Gender Undisclosed HSC 2009 Sep 3, 2008 #3 wow, good question =/ "4U MATH: 94"
V vds700 Member Joined Nov 9, 2007 Messages 861 Location Sydney Gender Male HSC 2008 Sep 3, 2008 #4 linxicm said: Can anyone help me with this question? first derivative for : f(X)=1/(X*LnX^2) and f(x) = 98+5x/(3x^2+1) many tks!!! Click to expand... why u asking this if u did ure hsc 3 years ago?
linxicm said: Can anyone help me with this question? first derivative for : f(X)=1/(X*LnX^2) and f(x) = 98+5x/(3x^2+1) many tks!!! Click to expand... why u asking this if u did ure hsc 3 years ago?
