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help with maths in focus (1 Viewer)
- Thread starter fredinho
- Start date
Fortify
♪웨딩드레스
- Joined
- Mar 20, 2007
- Messages
- 1,281
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- Male
- HSC
- 2009
Split [2^n + (2n-1)]; so:
A = 2^n and b = (2n-1)
So A = 2^1 + 2 ^ 2 + 2 ^ 3 + ... + 2^10
A = 2 (2^10 - 1) / (2 - 1) = 2046
Now:
B = (2(1)-1) + (2(2)-1) + ... + (2(10)-1)
B = 1 + 3 + ... + 19
B = 10/2 (1+19)
B = 100
Therefore:
S10 = A + B = 2146.
A = 2^n and b = (2n-1)
So A = 2^1 + 2 ^ 2 + 2 ^ 3 + ... + 2^10
A = 2 (2^10 - 1) / (2 - 1) = 2046
Now:
B = (2(1)-1) + (2(2)-1) + ... + (2(10)-1)
B = 1 + 3 + ... + 19
B = 10/2 (1+19)
B = 100
Therefore:
S10 = A + B = 2146.