help (1 Viewer)

AsuTeksu · Oct 15, 2023

Oh my, oh my, I hope that doesn't appear in the HSC...

jimmysmith560 · Oct 15, 2023

Would the following working help?

Part A:

$\text{In} \ \Delta BOE \ \text{and} \ \Delta COE \\ \\ \angle CEO = \angle BEO=90 \degree \ \text{(given)} \\ \\ \text{EO is common} \\ \\ BO=CO \ \text{(radii of a circle)} \\ \\ \therefore \Delta BOE \equiv \Delta COE \ \text{(RHS)}$

Part B:

user18181818 · Oct 15, 2023

jimmysmith560 said:
Would the following working help?

Part A:

$\text{In} \ \Delta BOE \ \text{and} \ \Delta COE \\ \\ \angle CEO = \angle BEO=90 \degree \ \text{(given)} \\ \\ \text{EO is common} \\ \\ BO=CO \ \text{(radii of a circle)} \\ \\ \therefore \Delta BOE \equiv \Delta COE \ \text{(RHS)}$

Part B:

View attachment 40569

yes thank you!

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help (1 Viewer)

user18181818

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