hsc paper (1 Viewer)

[skool :(]

hey i need some help
i have the success one 3 unit past paper book. im doin the 1986 paper n im gettin all of question 3 wrong. plzzzzzzz if anyone can post their answers. ill post the questions nywayz.


find the volume of the solid obtained when the region between the curves y=x^3 and y=x^2, from x=0 to x=1, is rotated about the x axis.
plz i really need the answer
thanx

 

[wogboy]

Volume

= (Volume of y=x^2 rotated) - (Volume of y = x^3 rotated)

= pi*integral(0->1, (x^2)^2 dx) - pi*integral (0->1, (x^3)^2 dx)

= pi * (integral(0->1, x^4 dx) - integral(0->1, x^6 dx))

= pi * [1/5 - 1/7] units^3

= 2*pi/35 units^3

Is that correct?