indefinite integral (1 Viewer)

[Mr Chi]

( 4x^3+3x^2+5/x^2 dx
)
I cant get these sought of ones can someone please help?

 

[insert-username]

You need to write out the individual parts of the fraction, cancel common factors, and then write in terms of negative indices if necessary:

(
) (4x³ + 3x² + 5)/x² dx

=
(
) (4x³)/x² + (3x²)/x² + 5/x² dx

=
(
)(4x + 3 + 5x^-2) dx

= 2x² + 3x - 5x^-1


I_F

 

[pLuvia]

∫ [4x³+3x²+5/x²] dx
Is this what you mean?

If so
∫ [4x³+3x²+5/x²] dx
= x⁴+x³-5/x + C

If it's ∫ [4x³+3x²+5]/[x²] dx
= ∫ [4x³/x²+3x²/x²+5/x²] dx
= ∫ [4x + 3 + 5x^-2]dx
= 2x² + 3x - 5x^-1 +C
= 2x² + 3x - 5/x +C

P.S insert-username you forgot to add C the constant

 

[insert-username]

Damn. Damn Damn Damn Damn Damn. I always forget the bloody constant!


I_F

 

[Riviet]

Don't forget again.

 

[insert-username]

I was doing some integration today, and I kept leaving it out! So friggin' annoying! Automatic one mark off!


I_F

 

[pLuvia]

lol, just keep practicing , just make a note before you do those questions in a test usually works if you remember to write it down