Just another maths question (1 Viewer)

DeathB4Life

Bánned
Joined
Feb 4, 2006
Messages
590
Gender
Male
HSC
2006
"The stock value of a company over the first 10 days of it being sold fluctuates according to the formula:

V=[t(t-7)^2] + 4

Where V is the value, in cents, of each share and t is the number of days after the intitial sale.

a. Find all extreme points in the first 10 days and their nature.

b. Find the point/s of inflection

c. Sketch the graph of V versus t for the first 10 days."

im stuck on just finding the min/max points:

product rule to differentiate t(t-7)^2

[2t(t-7)^2] + (t-7)^2

expanded:
= (t^2) - 14t + 49 + (2t^3) - (28t^2) + 98t
= (2t^3) - (27t^2) -42t + 49

how would i go about finding the stationary points?
 

Trev

stix
Joined
Jun 28, 2004
Messages
2,035
Location
Pine Palace, St. Lucia, Brisbane.
Gender
Male
HSC
2005
V = t.(t-7)²+4
dV/dt = t.2(t-7)+(t-7)² = (t-7)(2t+t-7) = (t-7)(3t-7).
Stationary points where dV/dt=0 so where t=7 or t=7/3 days.

You differentiated wrong.
To find the nature of these points test the gradient either side of each point.
To find points of inflection, diferentiate again.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top