MedVision ad

locus of z, where z=u-i/u-2 (1 Viewer)

member 6003

Member
Joined
Apr 20, 2022
Messages
83
Gender
Male
HSC
2023
1665701094630.png
a) If u is purely real
b) If u moves around a unit circle

no idea for both of them, a hint would be appreciated
 

okkk

Member
Joined
Oct 30, 2020
Messages
39
Gender
Male
HSC
2022
If the equation is in terms of z, it's hard to apply the conditions, so re-arrange in terms of u. This gives us u=(2z-i)/(z-1). Then if u is purely real, you know that Im[(2z-i)/(z-1)]=0, which you can find the locus of by letting z=x+iy. Similarly, if u moves around the unit circle, you know that |(2z-i)/(z-1)|=1, which you can then find the locus of using z=x+iy.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top