N newnoise New Member Joined Apr 7, 2009 Messages 3 Gender Male HSC 2010 Nov 15, 2009 #1 w= (z-i)/(z-2) w is purely imaginary i keep getting a circle with radius 1 and centre 1,0
gurmies Drover Joined Mar 20, 2008 Messages 1,209 Location North Bondi Gender Male HSC 2009 Nov 15, 2009 #2
h3ll h0und Member Joined Sep 19, 2008 Messages 341 Gender Male HSC 2010 Nov 26, 2009 #3 W= z-i / z-2 If w is imaginary w=+- ni argw = arg (z-i/z-2) therefore, +- pi/2 = arg (z-i) - arg (z-2) which is a circle with radius sqrt5/2 and centre (1,1/2)
W= z-i / z-2 If w is imaginary w=+- ni argw = arg (z-i/z-2) therefore, +- pi/2 = arg (z-i) - arg (z-2) which is a circle with radius sqrt5/2 and centre (1,1/2)