Evaluate: /4 | | [( x^2 - 1) / x] dx | /2 Please and ty.
Juliaan Member Joined Apr 30, 2008 Messages 92 Gender Male HSC 2009 Feb 26, 2009 #1 Evaluate: /4 | | [( x^2 - 1) / x] dx | /2 Please and ty.
W whackymac New Member Joined Dec 16, 2007 Messages 16 Gender Undisclosed HSC N/A Feb 26, 2009 #2 Divide the numerator individually, ie. (x^2 - 1) / x = x - (1 / x) Now integrate that instead, /4 | | x - (1/x) dx = [ (x^2)/2 - ln x ] -> then sub in the borders for your answer. | /2
Divide the numerator individually, ie. (x^2 - 1) / x = x - (1 / x) Now integrate that instead, /4 | | x - (1/x) dx = [ (x^2)/2 - ln x ] -> then sub in the borders for your answer. | /2
LoneWolf1990 Member Joined Mar 15, 2008 Messages 169 Gender Male HSC 2008 Feb 26, 2009 #3 /4 | | [( x^2 - 1) / x] dx | /2 = /4 | | [x - 1 / x] dx | /2 = 4 [x^2/2-lnx] 2 = (8-ln(4))-(2-ln(2)) =6-ln(4)+ln(2)
/4 | | [( x^2 - 1) / x] dx | /2 = /4 | | [x - 1 / x] dx | /2 = 4 [x^2/2-lnx] 2 = (8-ln(4))-(2-ln(2)) =6-ln(4)+ln(2)
Juliaan Member Joined Apr 30, 2008 Messages 92 Gender Male HSC 2009 Feb 26, 2009 #4 Thanks heaps guys ~