First find the circumference of your cylinder disc, then let the sides of the rectangle be x and y
Total perimeter
2x+2y=2*6*pi
x+y=6pi
Area
A=xy
Now make x or y the subject from the perimeter
i.e. if y were the subject: y=6pi-x
A=x(6pi-x)
A'=6pi-2x
A"=-2
Now find the turning point using A', and from observation that point will be a maximum since A''<0
Now then you say: The rectangle is a maximum when x=blah blah
Then simply find the other side, y, and then multiply both together to get the maximum area
Just from observation of the question, you should find that the x and y values are the same, since the largest area a rectangle could have is if it is a square
Answer should be 9pi2 cm2