Parabola as a locus!! (1 Viewer)

[velox]

Hey, this is prob a really dumb question but does every parabola in the form x^2= 4ay have its vertex as (0,0) ?? thanks!!!

 

[~*HSC 4 life*~]

Yes they all have vertex (0,0)

 

[velox]

thanks

 

[Calculon]

otherwise its x²=4ay+c where c is a constant

 

[CM_Tutor]

Or in a more general form, (x - h)² = 4a(y - k) has a vertex at (h, k).

 

[Winston]

http://www.boredofstudies.org/community/showthread.php?s=&threadid=27070

check this thread, i've replied with quite a brief summary of what you should know about the Parabola in terms of the Locus topic. I explained about the parabola at vertex (0,0) or at vertext (h,k)

 

[Collin]

The parabola, by definition is a locus anyway; eccentricity = 1.