MedVision ad

Plus/minus in inverse trig? (1 Viewer)

sinophile

Well-Known Member
Joined
Oct 25, 2008
Messages
1,339
Gender
Undisclosed
HSC
N/A
Ive scanned a question which I was confused about. Where ive circled it, couldn't you consider both negative and positive cases, thus giving two solutions? Can someone explain why you only consider the positive case? Or anything else?



Apologies for it being so big.
 

maths-bbqz

New Member
Joined
Mar 5, 2009
Messages
29
Location
http://you-have-chode.mybrute.com
Gender
Undisclosed
HSC
2010
Heres my thought:
when it's the square root of x squared, you only take the positive sol'n (since a square root must be positive) but if you have x squared = 1 to start off with, you take both the positive and the negative answer
for example, root 5 doesn't equal minus root root 5, since how can a square root of something produce a negative result over the real field? But if x squared equals 5, you would take both solutions
Hope this helps :D and sorry i dont know how to use the equation editor D:
 
Last edited:

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,385
Gender
Male
HSC
2006
For the inverse cosine function to exist, it can only take a derivative of - 6. Its domain would be:



in order for it to be a function. Under this domain, cos 2x is strictly positive so we don't worry about the negative case.

However, under other circumstances, you would need to consider both cases...
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top