polynomial question (1 Viewer)

[enigma_1]

the polynomial p(x) is divided by (x-1)(x+2). find the remainder, given p(1) = 2 and p(-2) = 5

[Hint: remainder may have degree 1]

 

[QZP]

Hint: P(x) = (x-1)(x+2)Q(x) + ax +b

 

[Kurosaki]

Since the divisor is of degree 2 then the remainder is of degree 1. Then it can be expressed in th form ax +b
Then P(x)=(x-1)(x+2)A(x)+ ax + b
Then sub in x=1 and x=-2 and solve simultaneously