problem on exponetials Please help please (1 Viewer)

[Steven12]

question is
find the equation of the normal to the curve y=(x*2)(e*2x)
where * is (to the power of).at point where x=1

i tried this equation many times but keep getting the wrong answer
the correct answer on the sheet is suppose to be

x+4(e*2)y-4(e*4)-1=0

but i couldnt get that


is there anyone outthere who could help me on this one
please pleaase

Im crap at maths and i dont want to screw up my half yearlies cos it contribute to my final hsc mark................ arrrrrrrrrrrrrr

 

[Heinz]

y=x²e^2x
y' = 2xe^2x + 2x²e^2x
@x=1, y = e²
@x = 1, y' = 2e² + 2e² = 4e²
:. normal = -1/ 4e²

y - e² = -1/ 4e²(x-1)
-4e²y + 4e⁴ = x-1
x + 4e²y - 4e⁴ - 1 = 0