J j@son New Member Joined Feb 10, 2006 Messages 9 Gender Male HSC 2006 Apr 5, 2006 #1 Given that a^2+b^2=23ab Show that (a+b/2)^2=23ab.
Trev stix Joined Jun 28, 2004 Messages 2,037 Location Pine Palace, St. Lucia, Brisbane. Gender Male HSC 2005 Apr 5, 2006 #2 I think there's a typo there? Last edited: Apr 5, 2006
J j@son New Member Joined Feb 10, 2006 Messages 9 Gender Male HSC 2006 Apr 5, 2006 #3 Trev said: I think there's a typo there? Click to expand... Sorry, its meant to be: given that a^2+b^2=23ab Show that [(a+b)/5]^2=ab
Trev said: I think there's a typo there? Click to expand... Sorry, its meant to be: given that a^2+b^2=23ab Show that [(a+b)/5]^2=ab
R Riviet . Joined Oct 11, 2005 Messages 5,593 Gender Undisclosed HSC N/A Apr 5, 2006 #4 LHS=[(a+b)/5]2 =(a2+b2+2ab)/25 =(23ab+2ab)/25 =25ab/25 =ab =RHS
Raginsheep Active Member Joined Jun 14, 2004 Messages 1,227 Gender Male HSC 2005 Apr 5, 2006 #5 LHS=[(a+b)/5]^2 =(a^2+b^2+2ab)/25 sub in a^2+b^2=23ab =(23ab+2ab)/25 =25ab/25 =ab =RHS Damn Riviet for posting it as I started typing it! Anywayz, what does logs have to do with it?
LHS=[(a+b)/5]^2 =(a^2+b^2+2ab)/25 sub in a^2+b^2=23ab =(23ab+2ab)/25 =25ab/25 =ab =RHS Damn Riviet for posting it as I started typing it! Anywayz, what does logs have to do with it?