S _ShiFTy_ Member Joined Aug 7, 2005 Messages 185 Gender Male HSC 2006 Nov 8, 2005 #1 Lets say for example z= (a+ib)^n Is Z conjugate just z=(a-ib)^n Or are there special cases?
A acmilan I'll stab ya Joined May 24, 2004 Messages 3,989 Location Jumanji Gender Male HSC N/A Nov 8, 2005 #2 conj [(a+ib)n] = conj[(a+ib)(a+ib)(a+ib)...(a+ib)] = conj[a+ib]conj[a+ib]conj[a+ib]...conj[a+ib] = (a-ib)(a-ib)(a-ib)...(a-ib) = (a-ib)n
conj [(a+ib)n] = conj[(a+ib)(a+ib)(a+ib)...(a+ib)] = conj[a+ib]conj[a+ib]conj[a+ib]...conj[a+ib] = (a-ib)(a-ib)(a-ib)...(a-ib) = (a-ib)n
S _ShiFTy_ Member Joined Aug 7, 2005 Messages 185 Gender Male HSC 2006 Nov 8, 2005 #3 Hahah, so simple..thx
