Someone Plz Help (1 Viewer)

[oobaga]

please help me with this question as i have had a five week holiday and forgotten how to do logs. lol

Here's the one i need help with:

(ln5x)/5x

Thanks. Could u plz explain the steps you take. Thanks again, any help would be awesome.

Sorry.. was in a hurry to write and forgot to state what u have to do with it. It is differentiate. i'm just not sure how to differentiate the top half: ln5x

 

[pLuvia]

What do you want to do?

If you want to differentiate it use the quotient rule
d/dx[(ln5x)/5x)]
=[5x(1/x)-5ln5x]/25x²
=(1-ln5x)/5x²

Integration is not possible with standard 2u/3u methods, you'll have to use integration by parts

 

[jyu]

What do you want to do?

If you want to differentiate it use the quotient rule
d/dx[(ln5x)/5x)]
=[5x(1/x)-5ln5x]/25x²
=(1-ln5x)/5x²

Integration is not possible with standard 2u/3u methods, you'll have to use integration by parts

:wave:

 

[haque]

:wave:

Yeah I was gonna say that but jyu's doing a good job answering all the q before any of us has even had a chacnne to look at it lol but in 3u they'll probably give a lead up that indicates this and that's what pLuvia prolly meant(and i think LottoX stated)

 

[pLuvia]

Sorry.. was in a hurry to write and forgot to state what u have to do with it. It is differentiate. i'm just not sure how to differentiate the top half: ln5x

To differentiate the ln5x use the general formula of

d/dx[ln{f(x)}]=f'(x)/f(x)

So for you example

d/dx[ln5x]=5/5x=1/x