Subtraction of inverse tan expressions -- help needed, please explain! (1 Viewer)

[blackops23]

Hi guys, quick question:

How is ???

I don't understand how it works, is there a particular rule???
How would I show/prove the result it in an exam?

Basically, I had the expression:
However the answer was: because apparently (from the solution).


So an explanation of this would be immensely appreciated!

Thanks )

 

[bar2]

something very similar was done before idiot

 

[thoth1]

Hi guys, quick question:

How is ???

I don't understand how it works, is there a particular rule???
How would I show/prove the result it in an exam?

An explanation would be immensely appreciated

Thanks.

u take tan of both sides. and on the LHS you will have to use the tan (A-B) result to prove it is equal to RHS.

if u still dont understand just ask and ill do it 4 u.

 

[blackops23]

u take tan of both sides. and on the LHS you will have to use the tan (A-B) result to prove it is equal to RHS.

if u still dont understand just ask and ill do it 4 u.

So... 2-1/1+(1)(2) = = 1/3

therefore: = ?

Is that the only way, i.e. there is no super fast formula i.e. using some relationship between the two numbers, 1 and 2etc?

 

[thoth1]

So... 2-1/1+(1)(2) = = 1/3

therefore: = ?

Is that the only way, i.e. there is no super fast formula i.e. using some relationship between the two numbers, 1 and 2etc?

i believe thats the only way, well at least thats wat i use everytime i see a question with that in it.

 

[hello-infidel]

So... 2-1/1+(1)(2) = = 1/3

therefore: = ?

Is that the only way, i.e. there is no super fast formula i.e. using some relationship between the two numbers, 1 and 2etc?

It seems like a pretty super fast method to me. How can you expect it be any faster?

It's like asking if there is a faster way to add two numbers.