Titration calculation problem (1 Viewer)

[thebigticket]

i know how to calculate the concentration of a single acid or base in a titrated mixture
but i want to know is how to find the concentration of the entire acid-base mixture together *

heres the sample qs that bugging me*
calculate the concentration of the mixture where*
500mL of 0.1M of HCl is mixed with 500mL of 0.05 M of NaOH*

Also is it possible to calculate the pH by subtracting the pH of the acid by the base*

or do u subtract the the concentration of the acid by the base and then using the pH formula to calculate the pH

 

[RiFiPi]

n = C.V (in litres)
Moles of HCl = 0.1 times 0.5 = 0.05 moles
Moles of NaOH = 0.05 times 0.5 = 0.025 moles

HCl will be in excess by 0.025 moles (HCl - NaOH)

This means there will be 0.025 moles of H+ ions left over (as opposed to left of OH- ions if the NaOH was in excess.)

The total volume of solution is now the combined volumes of each solution, i.e. 0.5L + 0.5L = 1L

We are now trying to find Conc of H+
C=n/V
C = 0.025/1
C (of H+ ions) = 0.025 M

pH = -log[H+]
= -log[0.025]
= 1.6

Hope that helped/I hope that's worked out right.