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Trignometric functions, need help p;z! (1 Viewer)

Thread starter excellence1
Start date Feb 29, 2016

excellence1

Member

Feb 29, 2016

Solve:

tan^2x-1= 0 between 0 and 2pi

KingOfActing

lukewarm mess

Feb 29, 2016

$$Assuming you meant $ 0 \leq x \leq 2\pi\\ \tan^2{x} - 1 = 0\\\tan{x} = \pm 1\\x = \frac{\pi}{4}, \frac{3\pi}{4}, \frac{\pi}{4} + \pi, \frac{3\pi}{4} + \pi$

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