el_manu
Member
Ok. You know how rhombus diagonals bisect the angles at the corners.
Does the same thing happen in squares?????
Does the same thing happen in squares?????
URGENT Geometry help URGENT! (1 Viewer)
- Thread starter el_manu
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Yes (a square is a special case of a rhombus, after all).
sharoooooo
Active Member
yep.
if u need proof, i guess you could say like if u draw the diagonals in the square, itd form 4 isos triangles. and the diagonals bisect the right angles. so the base angles of each isos = 45. so then the other angle must be 90. thus, perpendicular
if u need proof, i guess you could say like if u draw the diagonals in the square, itd form 4 isos triangles. and the diagonals bisect the right angles. so the base angles of each isos = 45. so then the other angle must be 90. thus, perpendicular
He wasn't asking whether the diagonals bisect each other at right angles (which they do), but whether the diagonals bisect the square's internal angles (which they also do). (This is easily proved by drawing a diagonal and noting that the triangles formed are isosceles and congruent.)
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