Urgent help with these two questions :) inverse functions (1 Viewer)

[petermik]

These two questions particularly the last part of the top question and all of the second

EDIT: Just the second question.

The furthest I can go is that it is the same intersection as with y=x

e^(2-y)=x
e^(2-x)=y and

but e^2-x=x is the same as e^2-y=x P.O.I
e^2-X - X=0 e^2-X =X which is true right ?

-e^2-y=dx/dy , dy/dx=-1/x
dy/dx= -e^2-x= -x from previously since e^2-x=x
m1m2=1
.... did i just answer my own question

 

[seanle]

hi if x = e^2-y, the differiate of this is -e^2-y .Then this is dx over dy and dy over dx will be the recripocal of -e^2-x. Times these together and you get -1.

 

[seanle]

sorry that will just be one.

 

[seanle]

sorry that will just be one.

 

[seanle]

sorry that will just be one.

 

[seanle]

with last question i got lne^2-lny for the inverse function

 

[seanle]

let f(x) = e^2 times e^-x. times both sides by e^x. take logs of both sides to get an expression for x. and then exchange x and y to get a inverse function.