LuthienAdrianna
Member
OK, this is what my textbook says about weak acids:
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Most acids are only partially ionised in water and are therefore classified as weak acids. The ionisation of the weak acid, ethanoic acid, can be represented by the following equations:
CH3COOH (aq) <--> H+(aq) + CH3COO- (aq)
or
CH3COOH (aq) + H2O (l) <--> H3O+ (aq) + CH3COO- (aq)
The reversible arrows indicate that an equilibrium is established between ethanoic acid molecules and hydrogen ions and ethanoate ions. In terms of the Bronsted-Lowry theory CH3COOH is a weaker acid (proton donor) than H3O+, and H2O is a weaker base (proton acceptor) than CH3COO-. The reverse reaction is therefore favoured, so that at equilibrium only a small proportion of ethanoic acid molecules are ionised.
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I don't get the bolded part. Could someone PLEASE explain this to me? Am feeling quite desperate.:worried:
~*~
Most acids are only partially ionised in water and are therefore classified as weak acids. The ionisation of the weak acid, ethanoic acid, can be represented by the following equations:
CH3COOH (aq) <--> H+(aq) + CH3COO- (aq)
or
CH3COOH (aq) + H2O (l) <--> H3O+ (aq) + CH3COO- (aq)
The reversible arrows indicate that an equilibrium is established between ethanoic acid molecules and hydrogen ions and ethanoate ions. In terms of the Bronsted-Lowry theory CH3COOH is a weaker acid (proton donor) than H3O+, and H2O is a weaker base (proton acceptor) than CH3COO-. The reverse reaction is therefore favoured, so that at equilibrium only a small proportion of ethanoic acid molecules are ionised.
~*~
I don't get the bolded part. Could someone PLEASE explain this to me? Am feeling quite desperate.:worried: