is the final answer:
(x-1)(3x^2-3x)+4y
(x-3)(x+3)(x-2)
by any chance?
be careful with the way you use the term 'imaginary numbers'I dont think so, I plugged in some imaginary numbers and it didnt work out the same... But maybe.. Working?
I dont think so, I plugged in some imaginary numbers and it didnt work out the same... But maybe.. Working?
It's taken me several a4 pages and a lot of angst and istill dont get it..its soooooooooo long, took me a whole a4 page
give it a few minutes..
edit: i put in some numbers as well, and it didnt work.. so i guess it doesnt
haha, yeah, i was like WTF when did imaginary numbers come into the two unit prelim course?! haha.be careful with the way you use the term 'imaginary numbers'
=)
Dear Deer - don't give up. You are not likely to get a problem of this complexity in 2U Maths HSC Exam. One of my concerns is whether or not you have transcribed the expression correctly?Its definately copied correctly, I just double checked.
Im so upset, I want to drop maths ;__;
the answer isErgh this is making me so frustrated
If someone could help that would be greatly appreciated.
2x+y/x-3 + x-y/x+3 - 3x+2y/x^2+x-6
It should be easy but it isn't happening for me.
the answer is
x^3+2y-6x^2
------------------
x^2
[= dont give up
i think i might have done it wrong :s butI got what the above got as well..
Do you mind posting your full solution? This question is killing me.
lol u took a+b/c to be a+b/c and not (a+b)/ci think i might have done it wrong :s but
2x+y/x-3 + x-y/x+3 - 3x+2y/x^2+x-6
2x+x-3x+x+y/x-y/x+2y/x^2-3+3-6
x+y/x-y/x+2y/x^2-6
(x^2)x+xy+x(-y)+1(2y)-(x^2)6
x^2+xy-xy+(2y)-x^2 times 6
-------------------------------------
x^2
x^2+1 xy-xy+2y-6x^2
------------------------------
x^2
x^3 +xy-xy+2y-6x^2
----------------------------
x^2
x^3+2y-6x^2
-----------------
x^2