I have exam tomoroow and i still don't know..can ne1 help (2 Viewers)

[SophJI]

Q find the exact area of the minor segment of a circle if

radius is 3m and angle subtended is pi/3



Q Find the area of the minor segment correct to 2 dpl givern

Radius 3.21 and the angle subtended is 1.22





can anyone explain

 

[staticsiscool]

omg no way me too

why are you doing mathematics

 

[Timothy.Siu]

Q find the exact area of the minor segment of a circle if

radius is 3m and angle subtended is pi/3



Q Find the area of the minor segment correct to 2 dpl givern

Radius 3.21 and the angle subtended is 1.22





can anyone explain

well the area of the minor segment would be the area of the sector minus the area of the triangle

u should revise the formulas.

 

[SophJI]

well the area of the minor segment would be the area of the sector minus the area of the triangle

u should revise the formulas.

i know the formula
i just can't get the answer

 

[singh.with.me]

with the 2nd qn: dont forget about radians...

 

[Timothy.Siu]

Q find the exact area of the minor segment of a circle if

radius is 3m and angle subtended is pi/3



Q Find the area of the minor segment correct to 2 dpl givern

Radius 3.21 and the angle subtended is 1.22





can anyone explain

area of sector=0.5r^2 @ where @=pi/3 r=3
=3pi/2

area of triangle=1/2 . 3x3xsin pi/3=9/4
area of segment=3pi/2-9/4
i hope thats right...haven't done this stuff in ages

q2. same method

 

[addikaye03]

Q find the exact area of the minor segment of a circle if

radius is 3m and angle subtended is pi/3

A(minor segment)=(1/2)r^2(@-sin@)
=9/2(pi/3-sinpi/3)

Then use your exact value triangles, see how you go

 

[Woteva636]

How'd yr exam go???

 

[zazzy1234]

Q find the exact area of the minor segment of a circle if

radius is 3m and angle subtended is pi/3



Q Find the area of the minor segment correct to 2 dpl givern

Radius 3.21 and the angle subtended is 1.22





can anyone explain

the formula is :

1/2 *r^2*(C-sinC)

let C= pi/3 and r= 3

0.5 *9*((pi/3)-(sin60))
then just solve

 

[Aquawhite]

I'm always to late put my input into these posts... or help lol. dam! XD

and I was like, Oh! I know this one.